Skip to main content

ALKALI METALS

 ALKALI METAL 

Alkali Metal are  lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr)

1.Physical state of alkali metal
  •  One electron in outermost shell & General formula ns¹. 
  •  Francium is radioactive element. 
  • All are silvery white. 
  • Light soft, malleable and ductile metals with metallic lustre. 
  •  Alkali metals are paramagnetic, diamagnetic and colourless in form of ions.
2.Atomic size of alkali metal 

  • Biggest in their respective period (except noble gas element) 
  • Size increases from Li to Fr due to addition of an extra shell.  Li < Na < K < Rb < Cs < Fr
3. Softness of alkali metal 
  • Alkali metals are soft because of-
 (i) Large atomic size
 (ii) BCC crystal structure (HCP in Li)

 (iii) Loose packing (68% packing efficiency) 

(iv) Weak metallic bond 

  • Cs is the softest metal in s-block

4. Melting point and boiling point of alkali metal 
  • Weak interatomic bonds are due to their large atomic radii and presence of only one valence electron hence melting point and boiling point are low. 
  • Decreasing order of melting point and boiling point of alkali metal  is Li > Na > K > Rb > Cs 
  • With the increase in the size of metal atom, the repulsion of the non-bonding electrons increases and therefore melting point and boiling point decreases from Li to Cs.
5. Electro positive character or Metallic character of alkali metal 
   Electropositive ∝ 1/ Ionisation potential
Due to their larger size electron can easily be removed to form M+ ion. Electro positive property increases from Li to Cs. 
6. Flame test  of alkali metal 
Alkali metals and their salts gives characteristic colour to bunsen flame. The flame energy causes an excitation of the outer most electron which on dropping back to ground state emits absorbed energy as visible light.
Example :
 Li-Crimson red 
Na-Golden yellow 
K-Violet 
Rb-Red violet 
Cs-Blue

7. Reaction of alkali metal with NH3

  •  2Li + NH3   ⟶ Li2NH (Lithimide) 
2Na + 2NH3  ⟶ 2NaNH2 + H2 ↑ (Sodamide) 

  •  Solubility in liquid ammonia 
 (i) All the alkali metals dissolves in NH3 (liq.) and produces blue solution. 
(ii) This blue solution conducts electricity and possesses strong reducing power, due to the presence of ammoniated electrons. 
Na(s) + (x+y) NH3 ⟶[Na(NH3 ) x ] + + [e(NH3 ) y ] – ammoniated electron 
(iii) This dilute solution is paramagnetic in nature

 8. Photo electric effect of alkali metal 

  • Atomic size of K, Rb and Cs is quite large, so their ionisation potential is very low.
  • Due to very low ionisation potential their valence shell electrons gets excited even by absorbing visible light. That's why Cs is used in photo cells.
9. Standard oxidation potential of alkali metal 

  • All the alkali metals have high +ve values of standard oxidation potential (tendency of releasing electrons in water or self ionic solutions).
  • So these are good reducing agent, having upper most positions in the electro chemical series. 
  • Li has highest standerd oxidation potential (+3.05 eV) due to its high hydration energy. Such that it converts into. Li+ ion by loosing one electron.
10. Hydration energy ( Heat of Hydration ) of alkali metal 

  • Alkali metals salts are generally soluble in water due to hydration of cations by water molecules.
  • Smaller the cation, greater is the degree of its hydration. 

11. Reducing property of alkali metal 

  • Since alkali metals have high standard oxidation potential, so these are strongest reductants. 
  • Reducing property increases down the group in gaseous or molten state

 Li+ < Na+ < K+ < Rb+ < Cs+ 

  • But in aqueous solution order is -

 Li+ > K+ ~ Rb+ > Cs+ > Na+

12. Reaction of alkali metal with air 

  • Alkali metals gets turnish in air due to the formation of oxide at their surface hence they are kept in kerosene or paraffin oil. 
  • These elements reacts with moist air to form carbonates 
4Na + O2 ⟶ 2Na2
Na2O + H2O ⟶ 2NaOH (moist) 
2NaOH + CO2 ⟶ Na2 CO3 + H2 O (in air) 
In dry air only Li gives nitride and oxide both while other elements gives only oxides.
13. Reaction of alkali metal with Oxygen 
  • Oxide ion [O2-] : 
Li forms only Li2 O (Lithium oxide). 
  • Peroxide [O2] -² : 
Na reacts with O2 to form peroxide (Na2O2 ). 
  • Super oxide [O2 ‐] :
 K, Rb and Cs forms MO2 type oxides (super oxides) in excess of O2 . So super oxides are paramagnetic and coloured. 

 Their stability order is – Normaloxide > Peroxide > Superoxide 

14. Reaction of alkali metal with water 

  • Alkali metals react vigorously with water forming hydroxides with the liberation of H2 . 

2M + 2H2O ⟶ 2MOH + H2 

  •  Reactivity with water increases from Li to Cs. 

Li ⟶ least reactive towards water 

Na ⟶ reacts vigorously

K ⟶ reacts producing a flame

Rb, Cs⟶ reacts explosively. 

  • These metals also reacts with alcohol gives alkoxide and H2

2Li + 2C2 H5 OH ⟶ 2C2H5O-Li+ + H2 

  •  Monoxides gives strongly alkaline solution with water 

M2 O + H2 O ⟶ 2MOH

15. Reaction of alkali metals with Halides 

  •  Alkali metals reacts directly with halogen to form MX 

(M – alkalimetal, X – Halide ion)

  • Ionic properties of MX increases from LiCl to CsCl 
  • LiCl is covalent in nature (due to polarisation of Cl– ion by small Li+ ion). hence it hydrolyses with water while rest are ionic so do not hydrolyse. 
  • K, Rb and Cs halides reacts with more halogens to gives polyhalides. 

KI + I2 ⟶KI3

K+   + I3-

 CsBr + Br2 ⟶CsBr3⟶Cs+ + Br3

16. Carbonates of alkali metals 

  • All the alkali metals forms M2CO3 type carbonates. 
  • Except Li2CO3 , all the carbonates are stable towards heat 

Li2CO3     ⟶ (heat)  Li2O + CO2 

  •  Thermal stability of carbonates ∝1/ф(Ionic potential) Order of stability is – 

Cs2CO3 > Rb2CO3 > K2CO3 > Na2CO3 > Li2CO3  

17.  Nitrates of alkali metal 

  • Alkali metals forms MNO3 type nitrates (M – alkali metal) 
  • Stability increases from LiNO3 to CsNO3 . LiNO3 decompoes into Lithium oxide & NO2 on heating. 

4LiNO3 ⟶(heat + oxide) 2Li2 O + 4NO2 + O2 

  • Other nitrates, on heating to give nitrite and oxygen.

MNO3⟶ (heat) 2MNO2 + O2

18. Nitrides of alkali metals

 Only Li reacts directly with N2 to form nitride which gives NH3 on reacting with water. 

6Li + N2 ⟶2Li3

 Li3N + 3H2O ⟶ 3LiOH + NH3

  19. Formation of amalgam with alkali metals 

  • Alkali metals gives amalgam with Hg. 
  • These metals reacts with other metals to give mixed metals (alloys)

20. Sulphates for alkali metals 
  • Alkali metals forms M2SO4 type sulphates.
  • All alkali metal sulphates are ionic. Ionic properties increases from Li to Cs. 
Li2SO4 < Na2SO4 < K2SO4 < Rb2SO4 < Cs2SO4 
  • Li2SO4 Least soluble in water. 
  • These sulphates on burning with C forms sulphides 
M2SO4 + 4C  →M2S + 4CO 
  • Except lithium, sulphates of IA group reacts with sulphates of trivalent metals like Fe+3, Cr+3, Al+3 etc. gives double salts called alum.
21. Reaction of alkali metals with acids
  • Reacts vigaorously with acids 
2M + H2SO4 ⟶ M2SO4 +H2

Comments

Popular posts from this blog

Molar : Understanding the Concept and Its Significance

Demystifying Molar: Understanding the Concept and Its Significance Introduction: In the field of chemistry, the concept of the mole, often referred to as "molar," serves as a fundamental unit of measurement. The molar is a crucial concept that allows scientists to quantify and understand the relationships between atoms, molecules, and reactions. In this blog, we will delve into the fascinating world of moles, exploring their definition, significance, and applications in various aspects of chemistry. What is a Molar? Simply put, a molar is a unit of measurement used in chemistry to quantify the amount of a substance. It provides a bridge between the microscopic world of atoms and molecules and the macroscopic world of everyday measurements. The molar is defined as the amount of a substance that contains as many entities (atoms, molecules, ions, etc.) as there are atoms in exactly 12 grams of carbon-12. This definition is based on Avogadro's number, which is approximately 6

Unveiling the Science Behind Washing Powders: Insights from a Chemist

Unveiling the Science Behind Washing Powders: Insights from a Chemist Introduction: In our everyday lives, we encounter numerous challenges, and one that most of us can relate to is laundry. The quest for cleaner, fresher, and more vibrant clothes has led to the development of various laundry detergents, including the ever-popular washing powders. As a chemist, I find the science behind these powders fascinating. In this blog, we will delve into the intricate world of washing powders, exploring their composition, working mechanisms, and the chemical reactions that make them effective . 1. Composition of Washing Powders: Washing powders are complex mixtures of chemicals carefully formulated to remove dirt, stains, and odors from fabrics. The composition of washing powders typically includes the following key components:  a. Surfactants:  These are the primary cleansing agents in washing powders. Surfactants contain both hydrophilic (water-attracting) and lipophilic (oil-attracting) prop

Understanding Molar Concentration: A Key Concept in Chemistry

 Understanding Molar Concentration: A Key Concept in Chemistry Chemistry is the science that deals with the properties, structure, and composition of matter. One crucial concept in chemistry is molar concentration, which plays a crucial role in many chemical calculations, including stoichiometry, dilution, and reactions. In this blog post, we will delve into the fundamentals of molar concentration and explore its significance in chemical reactions and laboratory experiments. What is Molar Concentration? Molar concentration, also known as molarity, is a measure of the amount of solute dissolved in a given volume of solution. It is defined as the number of moles of solute per liter of solution and is denoted by the symbol "M." The molar concentration of a solution is determined by dividing the number of moles of solute by the volume of the solution in liters. The formula for molarity is Molarity (M) = moles of solute / volume of solution (in liters) For example, if you dissolve